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x^2-4x-1350=0
a = 1; b = -4; c = -1350;
Δ = b2-4ac
Δ = -42-4·1·(-1350)
Δ = 5416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5416}=\sqrt{4*1354}=\sqrt{4}*\sqrt{1354}=2\sqrt{1354}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{1354}}{2*1}=\frac{4-2\sqrt{1354}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{1354}}{2*1}=\frac{4+2\sqrt{1354}}{2} $
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